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An easy question

 
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An easy question
Desert Sleet
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#1
02-24-2005, 11:20 PM
This a easy question I heard once and got it right first time!!...

How many times does the number 7 appear when you count from one to a hundred?

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Huma
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#2
02-24-2005, 11:32 PM
<blockquote id="quote"><font size="1" face="Verdana, Tahoma, Arial" id="quote">quote<hr height="1" noshade id="quote"><i>Originally posted by Desert Sleet</i>
<br />This a easy question I heard once and got it right first time!!...

How many times does the number 7 appear when you count from one to a hundred?

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If I could... Then I would... Turn back time!!

<hr height="1" noshade id="quote"></font id="quote"></blockquote id="quote">

i would have said 9 times[(], but when i started counting, i ended up with 10...
Mr. Whappaaaa
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#3
02-25-2005, 04:27 AM
<blockquote id="quote"><font size="1" face="Verdana, Tahoma, Arial" id="quote">quote<hr height="1" noshade id="quote">This a easy question I heard once and got it right first time!!...

How many times does the number 7 appear when you count from one to a hundred?<hr height="1" noshade id="quote"></font id="quote"></blockquote id="quote">

OHHH... Come on yaar DESERT dont make a laugh to us.[)]

By the way its 20 times ( roughly & quickest idea )

Am i right..?







ASIF ALI
farazthegreat
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#4
02-25-2005, 05:53 AM
21

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jbladeus
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#5
02-25-2005, 08:48 AM
you call this question easy?!!! [o]

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derivativetrader
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#6
02-25-2005, 09:18 AM
Isn't it 20 times?

DT
Desert Sleet
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#7
02-25-2005, 06:56 PM
Yes most of you are correct the answer is 20.

7, 17, 27, 37, 47, 57, 67, (7,7), 87, 97, 70, 71, 72, 73, 74, 75, 76, 78, 79

Huma and Faraz you stand corrected. I think Huma, you forgot 7 itself and the fact that 77 has two sevens, and also the 7's in the series of 70's.

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Huma
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#8
02-25-2005, 07:20 PM
<blockquote id="quote"><font size="1" face="Verdana, Tahoma, Arial" id="quote">quote<hr height="1" noshade id="quote"><i>Originally posted by Desert Sleet</i>
<br />Yes most of you are correct the answer is 20.

7, 17, 27, 37, 47, 57, 67, (7,7), 87, 97, 70, 71, 72, 73, 74, 75, 76, 78, 79

Huma and Faraz you stand corrected. I think Huma, you forgot 7 itself and the fact that 77 has two sevens, and also the 7's in the series of 70's.

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If I could... Then I would... Turn back time!!

<hr height="1" noshade id="quote"></font id="quote"></blockquote id="quote">

yeah, i did,,, (
derivativetrader
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#9
02-25-2005, 07:45 PM
Guybrush - It was an easy question considering you can get alot more difficult guesstimates during a typical interview (in UK).
I have been asked this question in the past!

DT
Mr. Whappaaaa
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#10
02-26-2005, 05:51 AM
Okhay.....Now the topic is being moved on to the different perspective..... Not a bad puzzle game ...


What is the most & least repeated number in 1 to 100 ? and how many times does that both numbers appear..?

You have just 50 seconds to approach that silly question [)]

Now the time is started.... 1 ...2 ....3 .....4 .....5 ....6 ...


ASIF ALI
Desert Sleet
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#11
02-27-2005, 05:35 AM
<blockquote id="quote"><font size="1" face="Verdana, Tahoma, Arial" id="quote">quote<hr height="1" noshade id="quote"><i>Originally posted by Mr. Whappaaaa</i>
<br />Okhay.....Now the topic is being moved on to the different perspective..... Not a bad puzzle game ...


What is the most & least repeated number in 1 to 100 ? and how many times does that both numbers appear..?

You have just 50 seconds to approach that silly question [)]

Now the time is started.... 1 ...2 ....3 .....4 .....5 ....6 ...


ASIF ALI
<hr height="1" noshade id="quote"></font id="quote"></blockquote id="quote">
50 Seconds gone.......[?]

<b>My answer is 1(most) and 0 (least) </b>
1 appears 21 times

1-10-11(twice)-12-13-14-15-16-17-18-19-21-31-41-51-61-71-81-91-100

All other numbers appear 20 times

Followed closely by 0.. which appears 11 times..



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If I could... Then I would... Turn back time!!
Desert Sleet
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#12
02-27-2005, 05:52 AM
Here is an other puzzle to keep this thread going. I hope other members will also contribute and share there opinions also.

Three men walk into a hotel and ask for a cheap room. The receptionist charges them $30. They have just gotten to their room when the bellboy showes up, says that the receptionist decided that he charged too much, and gives the three men each a dollar. (the receptionist had really given the bellboy five dollars but he kept two for himself).
think about it. each of the men paid nine dollars that's $27.
the bellboy kept two that's $29.
where is the other dollar?

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If I could... Then I would... Turn back time!!
farazthegreat
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#13
02-27-2005, 05:14 PM
Okay, time for me to make up for my earlier mistake...

The receptionist has $25, the men have $3 and the bellboy has $2. That makes $30.

Anotherway to put it would be that the $9 each of them paid includes the $2 of the bellboy, they have the remaining $3.



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bilal azhar
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#14
03-01-2005, 11:29 PM
LET X = Y
NOW multiplying both sides with x we have
x2 = xy
subtracting y2 from both sides
x2-y2 = xy - y2
(x+y)(x-y) = y(x-y)
x+y = y
now as we know that y=x so putting y=x in above equation
x+x = x
2x = x
2x/x = x/x

2 = 1

so i have proved that two is equal to one.how is that possible?



bilal
bilal azhar
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#15
03-03-2005, 07:15 AM
nobody knows the answer?
how the above prove is wrong?

hint The answer is within the prove

bilal
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